To determine the thickness of the wire drawn from a copper rod, we can utilize the principle of volume conservation. The volume of the copper rod must equal the volume of the wire.
The formula for the volume of a cylinder is given by:
V = ext{Area} imes ext{Height}
Where the area of the base is:
A = rac{ ext{π}d^2}{4}
For the copper rod:
Substituting the values:
V_{rod} = rac{ ext{π}(0.01)^2}{4} imes 0.08
ext{Calculating: } V_{rod} ext{ (approx.) } = 6.2832 imes 10^{-5} ext{ m}^3
Let the thickness of the wire be ext{t} (in meters). The volume of the wire can be represented as:
V_{wire} = rac{ ext{π}t^2}{4} imes ext{Length}
Where the length of the wire = 18 ext{ m}:
V_{wire} = rac{ ext{π}t^2}{4} imes 18
Setting the volumes equal:
V_{rod} = V_{wire}
6.2832 imes 10^{-5} = rac{ ext{π}t^2}{4} imes 18
Rearranging gives:
t^2 = rac{6.2832 imes 10^{-5} imes 4}{ ext{π} imes 18}
Calculating this yields:
t ext{ (approx.) } = 0.0025 ext{ m} = 2.5 ext{ mm}
Conclusion: The thickness of the wire is approximately 2.5 mm.
Memory Tip: Remember that the volume remains constant during the drawing process, making it essential to equate the volumes of both shapes.